(2x^2-3x+7)(-x-4)=

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Solution for (2x^2-3x+7)(-x-4)= equation:


Simplifying
(2x2 + -3x + 7)(-1x + -4) = 0

Reorder the terms:
(7 + -3x + 2x2)(-1x + -4) = 0

Reorder the terms:
(7 + -3x + 2x2)(-4 + -1x) = 0

Multiply (7 + -3x + 2x2) * (-4 + -1x)
(7(-4 + -1x) + -3x * (-4 + -1x) + 2x2 * (-4 + -1x)) = 0
((-4 * 7 + -1x * 7) + -3x * (-4 + -1x) + 2x2 * (-4 + -1x)) = 0
((-28 + -7x) + -3x * (-4 + -1x) + 2x2 * (-4 + -1x)) = 0
(-28 + -7x + (-4 * -3x + -1x * -3x) + 2x2 * (-4 + -1x)) = 0
(-28 + -7x + (12x + 3x2) + 2x2 * (-4 + -1x)) = 0
(-28 + -7x + 12x + 3x2 + (-4 * 2x2 + -1x * 2x2)) = 0
(-28 + -7x + 12x + 3x2 + (-8x2 + -2x3)) = 0

Combine like terms: -7x + 12x = 5x
(-28 + 5x + 3x2 + -8x2 + -2x3) = 0

Combine like terms: 3x2 + -8x2 = -5x2
(-28 + 5x + -5x2 + -2x3) = 0

Solving
-28 + 5x + -5x2 + -2x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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